Convert font image straight to QIcons
Fixes a compile error with recent Qt6 versions
This commit is contained in:
12
x26model.cpp
12
x26model.cpp
@@ -376,27 +376,25 @@ QVariant X26Model::data(const QModelIndex &index, int role) const
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break;
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case 0x21: // G1 mosaic character
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if (triplet.data() & 0x20)
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// Returning the bitmap as-is doesn't seem to work here
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// but putting it inside a QIcon... does?
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return QIcon(m_fontBitmap.charBitmap(triplet.data(), 24));
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return m_fontBitmap.charIcon(triplet.data(), 24);
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else if (triplet.data() >= 0x20)
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// Blast-through
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return QIcon(m_fontBitmap.charBitmap(triplet.data(), m_parentMainWidget->pageDecode()->cellG0CharacterSet(triplet.activePositionRow(), triplet.activePositionColumn())));
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return m_fontBitmap.charIcon(triplet.data(), m_parentMainWidget->pageDecode()->cellG0CharacterSet(triplet.activePositionRow(), triplet.activePositionColumn()));
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break;
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case 0x22: // G3 mosaic character at level 1.5
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case 0x2b: // G3 mosaic character at level >=2.5
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if (triplet.data() >= 0x20)
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return QIcon(m_fontBitmap.charBitmap(triplet.data(), 26));
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return m_fontBitmap.charIcon(triplet.data(), 26);
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break;
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case 0x2f: // G2 character
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if (triplet.data() >= 0x20)
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return QIcon(m_fontBitmap.charBitmap(triplet.data(), m_parentMainWidget->pageDecode()->cellG2CharacterSet(triplet.activePositionRow(), triplet.activePositionColumn())));
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return m_fontBitmap.charIcon(triplet.data(), m_parentMainWidget->pageDecode()->cellG2CharacterSet(triplet.activePositionRow(), triplet.activePositionColumn()));
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break;
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default:
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if (triplet.modeExt() == 0x29 || (triplet.modeExt() >= 0x30 && triplet.modeExt() <= 0x3f))
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// G0 character or G0 diacritical mark
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if (triplet.data() >= 0x20)
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return QIcon(m_fontBitmap.charBitmap(triplet.data(), m_parentMainWidget->pageDecode()->cellG0CharacterSet(triplet.activePositionRow(), triplet.activePositionColumn())));
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return m_fontBitmap.charIcon(triplet.data(), m_parentMainWidget->pageDecode()->cellG0CharacterSet(triplet.activePositionRow(), triplet.activePositionColumn()));
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}
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if (role == Qt::EditRole && index.column() == 2)
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